scripting! , how to do this ?

[rveri]

Hi All ,

I have this : data1.txt
--------
44%
53%
77%
61%
1%
3%
45%
49%
------

How to get this out put like this:
-----
44
53
77
61
1
3
45
49
-----

Thanks in advance.

[RAC_1 · Accepted solution]

tr -d '\%' < "your_file"

[Raj D.]

hi,

You can use this command:

# cat data1.txt | sed 's/%/ /'

44
53
77
61
1
3
45
49


Cheers,
Raj.

[Muthukumar_5]

# awk -F"%" '{ print $1; }' < inputfile > outputfile
# cut -d"%" -f1 < inputfile > outputfile

--
Muthu

[Muthukumar_5]

To update in the same file itself then,

# perl -pi -e 's/%//' filename

Lots of ways to do it.

--
Muthu

[rveri]

Thanks all ,
Muthu though # perl -pi -e 's/%//' filename , command not giving output. Rest all orking fine.

[Muthukumar_5]

hi,

perl -pi -e 's/%//' filename

will update in the file itself.

Example:

# cat filename
45%
35%

# perl -pi -e 's/%//' filename
# cat filename
45%
35%

It is not needing any temporary files to do this action.

If you don't want then simply as,

# perl -p -e 's/%//' filename (without -i)

--
Muthu

[Muthukumar_5]

oops,

# perl -pi -e 's/%//' filename
# cat filename
45
35

will remove % and update in the same file.

--
Muthu

[rveri]

Thanks Muthukumar ,

Its working!!