shell script - command grep

[Jairo Campana]

Hello :

I have folloging problem in script with grep:

/usr/bin/rsh 10.1.1.10 /usr/bin/grep camaro /opt/cars/log/chevrolet.log
echo $?
0
Its is Ok "camaro" exist in chevrolet.log

my problem is when execute grep

/usr/bin/rsh 10.1.1.10 /usr/bin/grep nissan /opt/cars/log/chevrolet.log
echo $?
0

the result is 0 , but word nissan no exist in chevrolet.log

the result it would have 1

as it can be the problem.

thanks

[RAC_1 · Accepted solution]

In both cases, the return status is of rsh command and not of grep command. (which is being executed on other host)

You will have to redirect the exit status of grep to some file and then read it seperately. Something like follows.

/usr/bin/rsh 10.1.1.10 "/usr/bin/grep camaro /opt/cars/log/chevrolet.log;echo $? > /tmp/test" ; /usr/bin/rsh 10.1.1.10 "cat /tmp/test"

Anil

[Pete Randall]

I suspect it is giving the result of the rsh command rather than your grep command.


Pete

[Jairo Campana]

thanks ; but
replace " for '

/usr/bin/rsh 10.1.1.10 '/usr/bin/grep camaro /opt/cars/log/chevrolet.log;echo $? > /tmp/test' ; /usr/bin/rsh 10.1.1.10 'cat /tmp/test'

[Biswajit Tripathy]

/usr/bin/rsh 10.1.1.10 '/usr/bin/grep camaro /opt/cars/log/chevrolet.log;echo $?'

- Biswajit

[harry d brown jr]

If you only want to know if the value is in the file and you don't care to see the line it is on, then use the -q option of grep, like this:

xyz=`remsh 10.1.1.10 'grep -q nissan /opt/cars/log/chevrolet.log;echo $?'`

echo $xyz|sed "s/\(.*\)\([0-9]\)$/\1/"

If you want to see the "output" and the "return code" then use this:

xyz=`remsh 10.1.1.10 'grep nissan /opt/cars/log/chevrolet.log;echo $?'`

This displays the output of the grep:
echo $xyz|sed "s/\(.*\)\([0-9]\)$/\1/"

This displays the output of the "return code":
echo $xyz|sed "s/\(.*\)\([0-2]\)$/\2/"

grep only has three return codes (see man grep) 0, 1 and 2.

live free or die
harry d brown jr