Shell script

[Leif Halvarsson_2]

Hi
I want to write a shell script that read a file and searches for lines beginning with # . I think I must use som kind of "pattern matching" (regular expression) but how do I get this work.

[Sebastian Galeski_1]

cat /tmp/file.txt |grep "^#"

[H.Merijn Brand (procura]

1. grep '^#' file
2. perl -ne 'm/^#/&&print' file

[Chris Wilshaw]

Leif,

cat | grep ^#

should be what you need.

[John Palmer · Accepted solution]

Hi,

grep will do this for you...

grep "^#"

will print all lines in which start with #.

If you want to process the lines in a script then you can write a shell script like this...

grep "^#" | {
while read LINE
do

done
}

Regards,
John

[U.SivaKumar_2]

hi,
you can try
#grep "#" filename
if you want more logic you can use awk
#man awk

regards,
U.SivaKumar

[John Carr_2]

Hi

these first options will return every line containing a # you need to test the first character of each line to get it right.

!#/usr/bin/ksh

for eachline in filename ;
do

if [[ eachline[0] -eq "#" ]] then
cat $eachline >> newfilename
fi

cant remember the syntax on the if statement can someone correct it please.

John.

[John Carr_2]

please ignore my last comment of course the ^ will do it.

John.