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тАО08-03-2010 03:10 PM
тАО08-03-2010 03:10 PM
I am installing Oracle on an HP-UX 11.31 Itanium machine and I am required to set 'shmmax' to the size of the machine's physical memory.
What I don't know how to do is properly translate the 98gb of physical memory that my machine has into the desired number of bytes that 'shmmax' uses. I don't know if it uses gb that are 1024 mb, or 1000 mb, or various similar things down the pike. How can I correctly translate this? Or is there a command which will give me the physical memory size in honest bytes suitable for usage in 'shmmax' as opposed to something like
/usr/contrib/bin/machinfo | grep -i Memory
or
dmesg | awk '/Physical/ { print "RAM Size = "$2/1024" "MB }'
or
/usr/sbin/dmesg | grep "Physical:"
which at least gives it in Kbytes but still, the translation to proper format for 'shmmax' is unknown.
Thanks,
-Ron Levy
maybe I should just take the value for 1gb and multiply by 98.
Solved! Go to Solution.
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тАО08-03-2010 04:10 PM
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тАО08-03-2010 04:11 PM
тАО08-03-2010 04:11 PM
Re: shmmax format
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тАО08-03-2010 10:14 PM
тАО08-03-2010 10:14 PM
Re: shmmax format
Because you know the kernel is grabby and wants that 2 Gb for itself? :-)
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тАО08-04-2010 09:20 AM
тАО08-04-2010 09:20 AM