Unix scripting Date formating

[Edward_12]

Hi there, I need some help.
I want to get the seconds after midnight. in the format 'sssss. I have tried:

H=$(date +%H)
M=$(date +%M)

S=$(($H*60*60)+($M*60))

It gives seconds for an old time.

Thanks

[Justo Exposito]

Hi Edward,

Something like that?

integer sec=0
integer sec1=0
integer sec2=0
integer Hour=$(date +%R | cut -d":" -f1)
integer Minute=$(date +%R | cut -d":" -f2)
(( sec1 = $Hour * 60 * 60 ))
(( sec2 = $Minute * 60 ))
(( sec = $sec1 + $sec2 ))

echo $sec

Regards,

Justo.

[harry d brown jr]

S=$(($H * 3600 + $M * 60 ))

live free or die
harry

[Dave Chamberlin]

try this:
S = `exec $H \* 3600 + $M \* 60'
echo $S

[James R. Ferguson]

Hi:

Seconds are available:

S=S=$(date +%S)

Then:

# let X=\($H*3600\)+\($M*60\)+$S

Regards!

...JRF...

[Dave Chamberlin]

correction -
S = `exec $H \* 3600 + $M \* 60`

[A. Clay Stephenson · Accepted solution]

Here is one simple solution. One thing to avoid is multiple date calls.

S=$(date '+%T' | awk -F: '{print ($1 * 3600) + ($2 * 60) + $3)')

[Rodney Hills]

Be sure you have balanced paraenthesis.

S=$((($H*60*60)+($M*60)))

The first $(( is for expressions calculation.
You need parenthesis to balance the formula.

-- Rod Hills