Want to determin the file system having more than or equal to 80% usage

[Durvesh Mendhekar]

I want to determine the file system of equal to or greater than 80% usage by using bdf command how can i do it.

[OFC_EDM · Accepted solution]

It tells you in the output.

Or do you mean you want to script an alert based on the bdf output?

Can you provide a sample of your bdf output?

[Steven E. Protter]

Shalom,

There are a number of scripts posted to itrc that will do this job, based on bdf output.

http://forums13.itrc.hp.com/service/forums/questionanswer.do?threadId=178514

This thread is the largest repsoitory.

Yes you will have to hunt a bit but that thread has the best selection.

SEP

[Ivan Krastev]

Something like that?

bdf /tmp/
Filesystem kbytes used avail %used Mounted on
/dev/vg00/lvol4 524288 215128 306848 41% /tmp


bdf /tmp/ | awk '/\//{print $5}'
41%


regards,
ivan

[Durvesh Mendhekar]

hi,

Thanks for the reply.
Is there any way rather using script.
Can i determine it by using the command like bdf and using any option with it.

Regards,
Durvesh

[OFC_EDM]

I attached a script I wrote called "dut" which i put in my path.

It uses the df -k command and was written on Tru64. May work on HP-UX.

Basically it displays mount points exceeding a threshold I control in the script. The DEFAULT is 85.

You can also manually assign a threshold when you run from prompt:

# dut 74

This would report any mount points exceeding 74%.

Cheers

(rename the script from dut.ksh to dut so it's easier to type at prompt)

[Ivan Krastev]

There is no such feature in bdf - see the manual http://docs.hp.com/en/B3921-90010/bdf.1M.html

Tou should use a script to calculate that.

regards,
ivan

[OFC_EDM]

I just looked at the script after I posted it and an extra character seems to have found it's way in.

The first line looks like
#!/usr/bin/ksh#

it should be
#!/usr/bin/ksh

Cheers

[OFC_EDM]

You may have to change the path to certain executables in the script.

Use the "which" command on your system to find out where they are.

such as
which awk
which grep


etc etc

[jenith christopher]

Hi,

This is the single line help you to get equal or more than 80%

#bdf | awk '{print $6,$5}' | awk '$2 >= 80'



REGARDS,
Jenith Christopher

[Suraj K Sankari]

Hi,

Please download this file (bdfmesg) from below link you will find this is a great tool written by Mr.Bill Hassell.

http://forums11.itrc.hp.com/service/forums/questionanswer.do?threadId=1291639

Just give

#bdfmesg -P 80 ##to find all file system which is using 80 or more then 80

Like so many output you can take from bdfmesg

Many Thanks to Mr.Bill Hassell to create a nice and useful tool.

Suraj

[VK2COT]

Hello,

Others gave you lot of useful choices.

One more (an example when you want to look
for file systems that used more than 80% os
space:

# bdf -k | sed -e 's/%//g' | awk '$5 >= 80'

But be warned, such simple one-lineRs can
fail if the names of logical volumes (LVM)
or plexes (VxVM) are longer and wrap into
second line. In that case, you need a
smarter solution (see references in previous posts in the Forum).

Cheers,

VK2COT (amateur radio and Morse code
instructor since 1971)

[James R. Ferguson]

Hi:

Everytime you see a pipe ('|') a new process is spawned. THe 'awk' utility as the ability to match regular expressions and to perform substitutions without resorting to pipes with 'grep' and 'sed'. For instance:

# bdf|awk '{sub("%","",$(NF-1));if ($(NF-1)>80) {print}}'

Regards!

...JRF...

[OFC_EDM]

James thanks for that last statement. My dut script is, I admit, very old.

I modified your statement to add the % back in for the print. As well as formatted it a bit so the output is easier to read.

df -k |awk '{sub("%","",$(NF-1));if ($(NF-1)>80) {printf "%-25s %-12s %-12s %-12s %-12s %s \n", $1, $2, $3, $4, $5, $6}}'

Cheers

[Durvesh Mendhekar]

Hi,

Thank u all.

Regards,
Durvesh