Why command "ls -u" difference with "find -atime?"

[akit3210]

I want to list last access file that more than 30 days. In this case command ls can't specific date, then I choose command find. but this result of 2 command difference. ls -lu is true. Why? or please suggest other statement.

Example of find command:
#find . -name "*.*" -atime +30 -exec ls -l {} \;
Example of ls command
#ls -lu

In same file show difference access time.

Thank you for every answer.

[Matti_Kurkela]

Your command
#find . -name "*.*" -atime +30 -exec ls -l {} \;

is _selecting_ files to display according to access time, but then _displaying_ the modification time, because the ls command does not have the -u option here.

To get the _access_ times of files that haven't been accessed in 30 days, you would have to add the -u option:

#find . -name "*.*" -atime +30 -exec ls -lu {} \;

Also remember that for find, "-atime +30" actually means "accessed more than 30 complete days ago". If you run this now today (17th October on 09:00), it will choose the files accessed at or before 16th September 09:00.

Apparently the algorithm in "find" command counts the number of days, then discards the fractions before comparing to the target number.

[akit3210]

Thank you very much Matti.

Very quickly response:

:)