writing a small script

[Berson Mark]

Hi

i m sorry , but i dont have a lot of knowlege with shelling ,

i want to write a script that will do this :

1. check in i have in / a core file
2. run the command file and what on the core file and report this info to a file .

i will run it on crontab so i dont need to run it with a loop .

thanks

[Pete Randall · Accepted solution]

I haven't been able to try this one but,

00 02 * * * /usr/bin/find / -type f -name "core" -exec file > /home/root/core_report {} \;

should probably be close to what you're looking for.


Pete

[Jean-Luc Oudart]

1) write a script :
e.g. name=/usr/local/bin/chk
#!/bin/sh

what $1 >/tmp/$1.what
file $1 >/tmp/$1.file

2) run the command
find / -name core -exec /usr/local/bin/chk {} \;

Regards,
Jean-Luc

[Pete Randall]

Sorry, I should have mentioned that that was intended to be a crontab entry running at 2:00 AM everyday.


Pete

[Mark Grant]

find . -name core -exec file {} \; -exec what {} \; >> outputfile

[Jeroen Peereboom]

If you only want to search in /, and not in other fielsystems, add a '-xdev' to your find statement.

find / -xdev -name core -type -exec file {} >> yourlogfile \;

This will only search the root filesystem, find regular (normal) files, and executes the 'file' command, and APPEND the output to yourlogfile.

Since you may want to execute several commands on 1 core-file, I think you should follow Jean-Luc's solution by writing a separate script to do this.


I would prefer something like:
#!/bin/sh

(
echo $1
what $1
file $1
) >> /root/yourlogfile

Or even put the date in the logfilename.
(something like: yourlogfile=/root/logfile`date "+...."`
and change the last line to:
) >> $yourlogfile

JP.