how to get the duplicate GID

[Soujanya]

How to write an awk program that reads /etc/passwd and prints the names of those users having the same GID in the form GID name1 name2 ......

Does the input data need to be sorted?


Any Help is much appreciated :)

Thanks in Advance
Soujanya.R

[Manuel Wolfshant]

The information is already available in /etc/group, no need to parse /etc/passwd.

[Manuel Wolfshant]

Oh, well, I stand corrected. Only for supplementary groups does /etc/group include the usernames. Primary group must be retrieved from /etc/passwd.

[Atul Gautam]

Hey Soujanya,

The command given below can give you a listing of the usernames and their GIDs but it will also contain the list of system users as well.

# awk -F: '{print $1 " " $4}' /etc/passwd





Atul

[Atul Gautam · Accepted solution]

Also,

With proper formatting, the output can be generated using the command ---

awk -F: '{print NR ". " $4 " "$1}' /etc/passwd





Atul