awk query

[Declan Heerey]

I'm trying to print the 2nd last word of a slash delimited string which is not always the same length

i.e.

http://vss:8080/svn/parallel/Product/one/that file.sql

or

http://vss:8080/svn/parallel/Product/section/one/that file.sql


In this case I always want the "one" to be printed

I have tried several different combos of awk but can only get it to work if i know how many fields are in the string :o(

Any help appreciated

[James R. Ferguson · Accepted solution]

Hi:

# awk -F/ '{print $(NF-1)}'

...as for example:

# X="http://vss:8080/svn/parallel/Product/one/that file.sql"

# echo ${X}|awk -F/ '{print $(NF-1)}'

Regards!

...JRF...

[Declan Heerey]

Thanks James

That's done the trick

Cheers

[Dennis Handly]

You of course can use:
$ echo $(basename $(dirname $XXX))

Where $XXX is the first string.