Script question

[Jeffrey F. Goldsmith]

My manager wanted me to modify our 'prt' script so that information from all the reports that are printed goes to a 'record' file. That seems to be working fine but sometimes we get some reports that have headers that are much longer and have caused us problems.
I tried to make a change to the script to keep any file headers of a certian length are ignored. With that change none of the header information is going into the 'record' file. Any ideas as to what I am doing wrong?
I am attaching the script and I also highlighted the part that I am having problems with.
Thanks for the help.

[Jeroen Peereboom · Accepted solution]

Hi Jeff,

you commented out 3 lines (around the rm -rf /tmpspool/.$$)? Is that the change you made?

I see 2 other things:
1)
if [ "$12" = '' ]
then
echo `date +%D-%X` $1 $2 $3 $4 $5 $6 $7 $8 >> /tmpspool/record
fi

$12? Is there a $12 in the call to your script? Do a short test by creating a script that prints $12 and ${12}!
$12 equals $1 followed by the digit 2 I'm afraid. So indeed it's never equal to '' and nothing gets logged.

2) There is a chmod command all alone on a line, without arguments.

In ksh you can also define a variable with a fixed length (typeset -L40: left justified, leading blanks removed, 40 chars, padded on the right with blanks if necessary). Maybe that's of any help.

JP

[Francisco J. Soler]

Hi, where are the part you have trouble?, i can't find it.

Frank.

[Jeffrey F. Goldsmith]

The part that I was having problems with was the following:

if [ "$12" = '' ]
then
echo `date +%D-%X` $1 $2 $3 $4 $5 $6 $7 $8 >> /tmpspool/record
fi

With your help I was able to figure out what needed to be fixed. This is what it now looks like and it seems to be working fine:

if [ "${12}" = '' ]
then
echo `date +%D-%X` $1 $2 $3 $4 $5 $6 $7 $8 >> /tmpspool/record
fi

I had to put brakets around the 12. Thanks for the help.