What is the meaning of @ itno a script???

[Manuales]

Sorry ..
into a script, what is the meaning of "@" as folows:

umask $@

thanks ...
Manuale.s

[James R. Ferguson · Accepted solution]

Hi Manuales:

In a shell script, $@ represents the (positional) arguments passwd to the script. For instance:

# cat my.sh
echo $@

# ./my.sh abc
abc

# ./my.sh abc def
abc def

Hence in the case you show, the assumption is that your script is to receive the octal umask value as an argument to set 'umask'.

Regards!

...JRF...

[Jeff Schussele]

Hi Manuale,

$@ is a positional parameter that provides a list of all arguments.

So does $*, BUT the key is that $@ provides a list of strings whereas $# provides *one* long string containing all arguments.

HTH,
Jeff

[James R. Ferguson]

Hi (again):

$# returns the decimal number of arguments passed.

$* is like $@ unless you double quote $* like:

"$*" in which case each positional parameter (argument) acts like you wrote:

$1${IFS}$2${IFS}...

...where ${IFS} is the current Inter Field Seperator.

Pass various arguments (one or more) to this script to see the differences:

# cat my.sh
#!/usr/bin/sh
IFS=":"
echo $@
echo $*
echo "$@"
echo "$*"

# ./my.sh a b c
# ./my.sh "a b c"

Regards!

...JRF...

[Manuales]

Thanks my friends !!!

:0)

Manuales.